A Train After Travelling 150 Km Meets With An Accident

Thus time taken at 30 kmph is 4 15 60 minutes and at 40 kmph is 3 15 45 minutes. Had the accident occured 24kms further it would have reached the destination only 25 minutes late.


A Train After Travelling 150 Km Meets With An Accident And Proc

Let A be the starting place.

A train after travelling 150 km meets with an accident. Train A mA 150000 kg is traveling west at 70 kmh. Find the total distance of travelling. A train met with an accident 120 km from station A.

Had an accident occurred 24 kms further it would have reached destination only 25 minutes late. It completed the remaining journey at frac56 of its previous speed and reached 2 hour late at station B. Because the engineer driving B fails to slow down B runs into the back of A.

If the train were to travel without stoppages it would cover 48 km. What is the total distance traveled by the train. What is the total distance traveled by the train.

Find the original speed of the train. Or 200a 625 a 200625. The speed of the train is.

Had the accident occurred 24 km further it would have reached the destination only 25 minutes late. Had the accident occurred 60 kms further on it would have reached 15 minutes sooner. A train after traveling 150 km meets with an accident and then proceeds with 35 of its former speed and arrives its destination 8 hours late.

With stoppages the average speed reduces by 48-40 8 km Therefore 848 60 minutes 10 minutes. A train meets with an accident and travels at 47th of its regular speed hereafter and hence it reaches its destination 36 minutes late. A train after traveling for 50km meets with an accident and then proceeds at 34 of its former speed and arrives at its destination 35 minutes late.

Using v2 u2 2aS. 4y3x - yx 712. Had the accident occurred 360 km further it would have reached the destination 4 hours late.

Had the acci- dent taken place 150 km further along the railway line the train would have arrived only 3 frac12hours late. The two trains stick together and then move as a single unit after the collision. A train after traveling 150 km meets with an accident and then proceeds with 35 of its former speed and arrives its destination 8 hours late.

A train after travelling 50 km meets with an accident and then proceeds at 34 of its former speed and arrives at its destination 35 minutes late. Find the speed of train. Hence the distance is given by 75 6460 8 km.

A train after travelling 50kms meets with an accident and then proceeds at 34th of its former speed and arrives at its destination 35 minutes late. Had the accident occurred 360 km further it would have reached the destination 4 hours late. Slower train u 11525 90 km h1.

The speed of the train is. 02 252 2a100. A train after travelling 50 km meet with an accident and then proceeds at 34th of its former speed and arrives at its destination 35 minutes late.

Hence the multiplying factor is 15. 70 miles Time Distance Speed Time 70 km 50 kmh Time 14 h 1 hour 60 minutes 04 h 04 60 04 h 24 minutes Time 1 hour 24 minutes Time 012400 HHMMSS Example 2. Due to which its speed reduces to 34 th of its original speed and in consequence 38 min late.

60 miles Time Distance Speed Time 60 miles 40 kmh 1 mile 1609344 km Time 60 1609344 km 40 kmh Time 9656064 km 40 km. It arrives at the destina- tion 4 hours late. Find the speed of the train and the distance.

300importantaptitudequestions Q no 187timeanddistancebyprabhakarsir careerAdhyapanA train after travelling 150 km meets with an accident and then proceeds. So y 3x4 - yx 3560. A train met with an accident 3 hours after starting which de- tains it for one hour after which it proceeds at 75 of its original speed.

40 kilometer per hour kmh Distance. Due to this it is 20 minutes late. 50 mile per hour kmh Distance.

Find the original time for the journey beyond the point of accident. A train meets with an accident and moves at 34 its original speed. After travelling 40 km a train meets an accident.

Ans normal speed 60 Kmhr distance ans 870 KM. What is the speed of the train. T 2 16025 64 minutes.

U 90 185. Had the accident taken place 300 km further it would have been only 1 hour late. Relative velocity of faster train wrt.

Had the accident happened 20km further on it would have arrived 12 minutes sooner. Solving mathematically S 1 S 2 t 2 t 2 32 575 t 2 t 2 32 5t 2 160 75 t 2. Ms1 25 ms1.

A train after travelling 100 kms from P meets with an accident and then proceeds at 34 th of its original speed and arrives at the terminus Q 90 minutes late. Train B mB 100000 kg behind train A on the same track is traveling west at 83 kmh and so is gaining on train A. A train after travelling 50km meets with an accident and then proceeds at 45 of its former rate and arrives at the terminal 45 minutes late.

Now you can use D S T 30 6060 30 km. Had the accident happened 60 km ahead from point of accident then in consequence 26 min late.


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